๊ด€๋ฆฌ ๋ฉ”๋‰ด

Jerry

[ํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค/SQL ๊ณ ๋“์  Kit] ๋™๋ช… ๋™๋ฌผ ์ˆ˜ ์ฐพ๊ธฐ ๋ณธ๋ฌธ

Problem Solving/SQL ๋ฌธ์ œ ํ’€๊ธฐ

[ํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค/SQL ๊ณ ๋“์  Kit] ๋™๋ช… ๋™๋ฌผ ์ˆ˜ ์ฐพ๊ธฐ

juicyjerry 2023. 11. 7. 09:18
๋ฐ˜์‘ํ˜•

๐Ÿ’ช๋ฌธ์ œ
๋™๋ฌผ ๋ณดํ˜ธ์†Œ์— ๋“ค์–ด์˜จ ๋™๋ฌผ ์ด๋ฆ„ ์ค‘ ๋‘ ๋ฒˆ ์ด์ƒ ์“ฐ์ธ ์ด๋ฆ„๊ณผ ํ•ด๋‹น ์ด๋ฆ„์ด ์“ฐ์ธ ํšŸ์ˆ˜๋ฅผ ์กฐํšŒํ•˜๋Š” SQL๋ฌธ์„ ์ž‘์„ฑํ•ด์ฃผ์„ธ์š”. ์ด๋•Œ ๊ฒฐ๊ณผ๋Š” ์ด๋ฆ„์ด ์—†๋Š” ๋™๋ฌผ์€ ์ง‘๊ณ„์—์„œ ์ œ์™ธํ•˜๋ฉฐ, ๊ฒฐ๊ณผ๋Š” ์ด๋ฆ„ ์ˆœ์œผ๋กœ ์กฐํšŒํ•ด์ฃผ์„ธ์š”.

 

ํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค

์ฝ”๋“œ ์ค‘์‹ฌ์˜ ๊ฐœ๋ฐœ์ž ์ฑ„์šฉ. ์Šคํƒ ๊ธฐ๋ฐ˜์˜ ํฌ์ง€์…˜ ๋งค์นญ. ํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค์˜ ๊ฐœ๋ฐœ์ž ๋งž์ถคํ˜• ํ”„๋กœํ•„์„ ๋“ฑ๋กํ•˜๊ณ , ๋‚˜์™€ ๊ธฐ์ˆ  ๊ถํ•ฉ์ด ์ž˜ ๋งž๋Š” ๊ธฐ์—…๋“ค์„ ๋งค์นญ ๋ฐ›์œผ์„ธ์š”.

programmers.co.kr

 

 

 

๐Ÿ’ช ๋‚˜์˜ ์ •๋‹ต

SELECT NAME, COUNT(*) AS 'COUNT'
FROM ANIMAL_INS
GROUP BY NAME
HAVING COUNT >= 2
AND NAME IS NOT NULL
ORDER BY NAME;

 

 

 

๐Ÿ’ช ๋‹ค๋ฅธ ์ •๋‹ต

SELECT NAME
      ,COUNT(NAME)
  FROM ANIMAL_INS
 WHERE NAME IS NOT NULL
 GROUP BY NAME 
       HAVING COUNT(NAME) > 1
 ORDER BY NAME;



 

๐Ÿ’ช ๋ฐฐ์šด ์ 

- "WHERE์ ˆ์—์„œ ์šฐ์„ ์ ์œผ๋กœ ํ•„ํ„ฐ๋ฅผ ํ•˜๋Š” ๊ฒƒ๊ณผ HAVING์ ˆ์—์„œ ํ•„ํ„ฐ๋ฅผ ํ•˜๋Š” ๊ฒƒ๊ณผ์˜ ์ฐจ์ด๊ฐ€ ๋ฌด์—‡์ผ๊นŒ?"๊ฐ€ ๊ถ๊ธˆํ•˜๋‹ค.

 

 

 

๐Ÿ’ช ๋งˆ์น˜๋ฉด์„œ

๋‹ค์Œ์—๋Š” ๋‹ค๋ฅธ ๋ฌธ์ œ๋กœ ์ฐพ์•„๋ต™๊ฒ ์Šต๋‹ˆ๋‹ค!

์•ˆ๋…• :))

 

 

 

 

๋ฐ˜์‘ํ˜•